51+15x-4.9x^2=0

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Solution for 51+15x-4.9x^2=0 equation:



51+15x-4.9x^2=0
a = -4.9; b = 15; c = +51;
Δ = b2-4ac
Δ = 152-4·(-4.9)·51
Δ = 1224.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{1224.6}}{2*-4.9}=\frac{-15-\sqrt{1224.6}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{1224.6}}{2*-4.9}=\frac{-15+\sqrt{1224.6}}{-9.8} $

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